erdős #267
Let and be the Fibonacci sequence. Let be an infinite sequence with . Mustbe irrational?
Open problem — our best result is machine-sealed: partial proof, reproduced by an independent verifier. The conjecture itself is unsettled.
irrationality · open · formalized (Lean) · 3 attempts
use this record
vela registry pull vfr_37aec80d874a0239vela reproduce examples/erdos-problemsevidence
honest null
needs verification
attempted via frontier '?' (transfer_strength=n/a) -> no_progress
No solve/partial on this pass. Transfer into the owned frontier was 'n/a'. Do not re-attack cold; needs a new idea or richer accumulated context.
partial proof
needs verification
erdos_267 (Fibonacci reciprocal irrationality): the strong form holds for ALL c>=2 (not just c>2) via Badea's criterion (Glasgow Math J 1987) — a KNOWN theorem applied. Formalizable, not novel.
Badea's irrationality criterion for sum 1/a_k with a_{k+1} >= a_k^2 - a_k + 1; applies to the lacunary Fibonacci indices. Result is the known answer, cleanly justified.
Opus cross-check; Badea 1987 cited.
partial proof
machine-sealed
Erdos #267: lean/Vela/Erdos267.lean formalizes the reduction from eventual ratio c >= 2 to Badea's eventual growth condition and, assuming Badea 1993 Corollary 3.2 as a published theorem input, derives the known c >= 2 Fibonacci reciprocal-subseries territory; this does not address the open 1 < c < 2 range.
{"lean_file":"lean/Vela/Erdos267.lean","imported_by":"lean/Vela.lean","formalized_items":["FibonacciReciprocalSubseries using Nat.fib and an infinite Real tsum","BadeaGrowth: eventually 2*n(k)-1 <=...
depends on (the wall): lean/Vela/Erdos267.lean; lean/Vela.lean
[{"method":"lean_kernel","command":"cd lean && lake build Vela.Erdos267","result":"passed"},{"method":"axiom_sorry_scan","command":"rg -n \"sorry|axiom|unsafe|admit\" lean/Vela/Erdos267.lean lean/V...
unverified AI candidates (2)
gpt-erdos · GPT-5.2 Pro + Deep Research · unverified
This is an Erdős–Graham problem (1980), and as stated with only the hypothesis (\displaystyle \frac{n_{k+1}}{n_k}\ge c>1), it is **not known in full generality**.
candidate solution ↗llm-hunter · gpt pro 5.2 · unverified
1 LLM attack(s) recorded (gpt pro 5.2); unverified.
candidate solution ↗formal
AMS 11 · open (literature)
theorem erdos_267 : answer(sorry) ↔ ∀ᵉ (n : ℕ → ℕ) (c > (1 : ℚ)), StrictMono n → (∀ k, c ≤ n (k+1) / n k) →
Irrational (∑' k, 1 / (Nat.fib <| n k))formal-conjectures/267.lean ↗Vela formalization: Erdos267.lean (sorry-free)
status
open