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For every let be a bounded set with outer measure . Must there exist an infinite independent set, that is, some infinite such that for all ?If the sets are closed and have measure , then must there exist an independent set of size ?

Worked, still open.

combinatorics · open · formalized (Lean) · 0 attempts

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vela reproduce examples/erdos-problems

evidence

unverified AI candidates (2)

gpt-erdos · GPT-5.2 Pro + Deep Research · unverified

Let (F(x)=A_x). Your “independent set” is what set theorists usually call a **free set** for the set mapping $F$: a set (X\subseteq\mathbb R) such that for all distinct (x,y\in X), (x\notin F(y)).

candidate solution ↗

llm-hunter · gpt pro 5.2 · unverified

1 LLM attack(s) recorded (gpt pro 5.2); unverified.

candidate solution ↗

formal

AMS 5 28 · open (literature)

theorem erdos_501 : answer(sorry) ↔
    ∀ (A : ℝ → Set ℝ),
      (∀ x, Bornology.IsBounded (A x)) →
      (∀ x, volume.toOuterMeasure (A x) < 1) →
      ∃ X : Set ℝ, X.Infinite ∧ X.Pairwise (fun x y => x ∉ A y)
formal-conjectures/501.lean ↗

status

open

notary

vela reproduce examples/erdos-problems
  • packet.json · sha256 0d24022c1ecad0df150d2f6533ef3058744387324a0808f87994716572ffeb24

finding.noted · reviewer:will-blair · 1 day

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