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For any graph is there some such that every graph on vertices that does not contain as an induced subgraph contains either a complete graph or independent set on vertices?

Worked, still open.

graph theory · open · formalized (Lean) · 0 attempts

machinery: graph-coloring,ramsey-theory,induced-subgraph-free,erdos-hajnal,homogeneous-set-bound,extremal-graph-theory,vertex-substitution-closure

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vela registry pull vfr_37aec80d874a0239
vela reproduce examples/erdos-problems

evidence

unverified AI candidates (2)

gpt-erdos · GPT-5.2 Pro + Deep Research · unverified

What you’re asking is exactly the **Erdős–Hajnal conjecture**.

candidate solution ↗

llm-hunter · gpt 5.2, gpt pro 5.2 · unverified

3 LLM attack(s) recorded (gpt 5.2, gpt pro 5.2); unverified.

candidate solution ↗

formal

AMS 5 · open (literature)

theorem erdos_61 :
    answer(sorry) ↔ ∀ {α : Type*} [Fintype α] [DecidableEq α] (H : SimpleGraph α),
      ∃ c > (0 : ℝ), IsErdosHajnalLowerBound H (fun n : ℕ => (n : ℝ) ^ c)
formal-conjectures/61.lean ↗

status

open

notary

vela reproduce examples/erdos-problems
  • packet.json · sha256 f4dddd6bb82982515bc9a23ee2cf6034888d249b29261ac8b000ae05e098db5a

finding.noted · reviewer:will-blair · 1 day

renders the record as of vev_d199cb2e · 1,338 events · hub

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