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Let count the number of powerful (if then ) integers in . Estimate . In particular is there some constant such thatand, for infinitely many ,

Worked, still open.

number theory · open · possible · formalized (Lean) · 0 attempts

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vela reproduce examples/erdos-problems

evidence

unverified AI candidates (2)

gpt-erdos · GPT-5.2 Pro + Deep Research · unverified

Write (F_2) for the squarefull (powerful) integers and (Q(x):=|\\{m\le x:m\in F_2\\}|). A standard fact is that every squarefull integer has a unique representation [ m=a^2b^3\qquad(b\ \text{squarefree}), ] and Erdős–Szekeres proved (with an explicit constant) [ Q(x)=c_2 x^{1/2}+O(x^{1/3}),\qquad c_2=\frac{\zeta(3/2)}{…

candidate solution ↗

llm-hunter · gpt pro 5.2 · unverified

1 LLM attack(s) recorded (gpt pro 5.2); unverified.

candidate solution ↗

formal

AMS 11 · open (literature)

theorem erdos_942 : answer(sorry) ↔ ∃ c > 0, ∃ (o : ℕ → ℝ), o =o[atTop] (1 : ℕ → ℝ) ∧
    (∀ᶠ n in atTop, erdos_942.h n < (Real.log n) ^ (c + o n)) ∧
    {n | erdos_942.h n > (Real.log n) ^ (c - o n)}.Infinite
formal-conjectures/942.lean ↗

status

open

notary

vela reproduce examples/erdos-problems
  • packet.json · sha256 29709835f322b8e6c2da556fcb58f7e79b4f6b1fb800c16cc59a2a882aa54b89

finding.noted · reviewer:will-blair · 2 days

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