erdős #942
Let count the number of powerful (if then ) integers in . Estimate . In particular is there some constant such thatand, for infinitely many ,
Worked, still open.
number theory · open · possible · formalized (Lean) · 0 attempts
use this record
vela registry pull vfr_37aec80d874a0239vela reproduce examples/erdos-problemsevidence
unverified AI candidates (2)
gpt-erdos · GPT-5.2 Pro + Deep Research · unverified
Write (F_2) for the squarefull (powerful) integers and (Q(x):=|\\{m\le x:m\in F_2\\}|). A standard fact is that every squarefull integer has a unique representation [ m=a^2b^3\qquad(b\ \text{squarefree}), ] and Erdős–Szekeres proved (with an explicit constant) [ Q(x)=c_2 x^{1/2}+O(x^{1/3}),\qquad c_2=\frac{\zeta(3/2)}{…
candidate solution ↗llm-hunter · gpt pro 5.2 · unverified
1 LLM attack(s) recorded (gpt pro 5.2); unverified.
candidate solution ↗formal
AMS 11 · open (literature)
theorem erdos_942 : answer(sorry) ↔ ∃ c > 0, ∃ (o : ℕ → ℝ), o =o[atTop] (1 : ℕ → ℝ) ∧
(∀ᶠ n in atTop, erdos_942.h n < (Real.log n) ^ (c + o n)) ∧
{n | erdos_942.h n > (Real.log n) ^ (c - o n)}.Infiniteformal-conjectures/942.lean ↗status
open