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Let be the minimal such that every set of consecutive integers contains an integer divisible by a prime . Estimate .

Worked, still open.

number theory · open · formalized (Lean) · 0 attempts

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vela reproduce examples/erdos-problems

evidence

unverified AI candidates (2)

gpt-erdos · GPT-5.2 Pro + Deep Research · unverified

Write $P(n)$ for the largest prime divisor of $n$. Your condition is equivalent to saying that for every (m>k), [ P\bigl(m(m+1)\cdots(m+n-1)\bigr)>k, ] because a prime (>k) divides the product iff it divides at least one of the $n$ factors. This is exactly the Erdős function $f(k)$ studied in the literature.

candidate solution ↗

llm-hunter · gpt pro 5.2 · unverified

1 LLM attack(s) recorded (gpt pro 5.2); unverified.

candidate solution ↗

formal

AMS 11 · solved (literature)

theorem erdos_961.sylvester_schur (k : ℕ) (hk : 0 < k) : Erdos961Prop k k
formal-conjectures/961.lean ↗

oeis

status

open

notary

vela reproduce examples/erdos-problems
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finding.noted · reviewer:will-blair · 1 day

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