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Let be an irreducible polynomial of degree (and suppose that for any ) such that the leading coefficient of is positive.Does the set of integers for which is -power-free have positive density?If , and for all primes there exists such that , then are there infinitely many for which is -power-free?In particular, doesrepresent infinitely many squarefree numbers?

Worked, still open.

number theory · open · possible · formalized (Lean) · 0 attempts

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vela registry pull vfr_37aec80d874a0239
vela reproduce examples/erdos-problems

evidence

unverified AI candidates (2)

gpt-erdos · GPT-5.2 Pro + Deep Research · unverified

Let me write (d:=\deg f) [[nomath]](so $d=k$ in your notation)[[/nomath]]. An integer $m$ is **$r$-power-free** [[nomath]](often: **$r$-free**)[[/nomath]] if no prime power (p^r) divides $m$.

candidate solution ↗

llm-hunter · gpt pro 5.2 · unverified

1 LLM attack(s) recorded (gpt pro 5.2); unverified.

candidate solution ↗

formal

AMS 11 · solved (literature)

theorem erdos_978.variants.sub_one {f : ℤ[X]} (hi : Irreducible f) (hd : 2 < f.natDegree)
    (hp : ∀ (x : ℕ), f.natDegree ≠ 2 ^ x) (hlc : 0 < f.leadingCoeff) :
    {n : ℕ | Powerfree (f.natDegree - 1) (f.eval (n : ℤ))}.Infinite
formal-conjectures/978.lean ↗

status

open

notary

vela reproduce examples/erdos-problems
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