For any , if is a sufficiently large finite Sidon set then there are at least many such that .

claimed — no verifier run, no signed judgmentunreviewedOpen. Worked here; no verified result yet.

sidon sets · solved · formalized (Lean) · 0 attempts

machinery: Sidon/B_h,additive-combinatorics,consecutive-integer-window,extremal-set-system

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vela registry pull vfr_37aec80d874a0239
vela reproduce examples/erdos-problems

Evidence

alphaproof · AlphaProof Nexus (DeepMind) · machine-verified (Lean)

Machine-verified Lean proof (kernel-checkable, sorry-free).

Lean proof ↗
unverified AI candidates (2)

gpt-erdos · GPT-5.2 Pro + Deep Research · unverified

Let (A={a_1<a_2<\dots<a_k}\subset\mathbb N) be a finite **Sidon set** [[nomath]](i.e. all sums $a_i+a_j$ with $i\le j$ are distinct)[[/nomath]]. Put [ S:=A+A={a_i+a_j:\ 1\le i\le j\le k}. ] Then the condition

candidate solution ↗

llm-hunter · gpt pro 5.2 · unverified

1 LLM attack(s) recorded (gpt pro 5.2); unverified.

candidate solution ↗

Formal proof1

AMS 5 · solved (literature)

theorem erdos_152 : answer(True) ↔ Tendsto f atTop atTop
formal-conjectures/152.lean ↗

Kernel-checked proof; human-attested statement.

  • faithful reviewer:will-blair erdos_152.lean

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  • packet.json · sha256 d003d4f4cd141668da929b020582810d983cd2239b27c6a2223a0a19a0d01ab4

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