Let be an infinite sequence such that, for any choice of congruence classes , the set of integers not satisfying any of the congruences has density . Is it true that for every there exists some such that, for every choice of congruence classes , the density of integers not satisfying any of the congruences for is less than ?

claimed — no verifier run, no signed judgmentunreviewedOpen. Worked here; no verified result yet.

number theory · solved · 0 attempts

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vela registry pull vfr_37aec80d874a0239
vela reproduce examples/erdos-problems

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unverified AI candidates (2)

gpt-erdos · GPT-5.2 Pro + Deep Research · unverified

It’s convenient to package the residue choices into a compact parameter space and then use a standard compactness/uniformity principle (Dini’s theorem). The only nontrivial point is to show that, for each fixed choice of residues, the densities for the *finite truncations* actually tend to $0$.

candidate solution ↗

llm-hunter · gpt 5.2 · unverified

1 LLM attack(s) recorded (gpt 5.2); unverified.

candidate solution ↗

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