Does every convex polygon have a vertex with no other vertices equidistant from it?

claimed — no verifier run, no signed judgmentunreviewedOpen. Worked here; no verified result yet.

geometry · open · prize $100 · formalized (Lean) · 0 attempts

machinery: geometric,equidistant-vertices,convex-position,unit-distance-graph,finite-configuration-witness,erdos-distinct-distances

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Evidence

unverified AI candidates (2)

gpt-erdos · GPT-5.2 Pro + Deep Research · unverified

This is a classic Erdős question (often listed as **Erdős Problem #97**) and it is **open**: it is not known whether *every* convex polygon must have a vertex from which you **cannot** find four other vertices all at the same distance. ([erdosproblems.com][1])

candidate solution ↗

llm-hunter · gpt 5.2, gpt pro 5.2 · unverified

2 LLM attack(s) recorded (gpt 5.2, gpt pro 5.2); unverified.

candidate solution ↗

Formal proof

AMS 52 · open (literature)

theorem erdos_97 :
    answer(sorry) ↔ ∀ A : Finset ℝ², A.Nonempty → ConvexIndep A → ¬HasNEquidistantProperty 4 A
formal-conjectures/97.lean ↗

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